1. Definition
When D²+E²−4F>0, x²+y²+Dx+Ey+F=0 is a circle with center (−D/2,−E/2) and radius ½√(D²+E²−4F).
3. Properties & Laws
- Complete the square;
- r=½√(D²+E²−4F);
- Condition >0 (=0 point, <0 none);
- Equal x²,y² coefficients, no xy term.
4. Steps
- Enter D,E,F;
- Click "Center & Radius";
- Or click "Load Example".
5. Worked Examples
Example: gives center (2,3), r=2.
6. Common Pitfalls
Mind the condition;
Center is negative half;
Use −4F.